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############################################################################
#
#	File:     calendat.icn
#
#	Subject:  Procedure to get date from Julian Day Number
#
#	Author:   Ralph E. Griswold
#
#	Date:     March 25, 2002
#
############################################################################
#
#   This file is in the public domain.
#
############################################################################
#
#  calendat(j) return a record with the month, day, and year corresponding
#  to the Julian Date Number j.
#
############################################################################
#
#  Acknowledgement:  This procedure is based on an algorithm given in
#  "Numerical Recipes; The Art of Scientific Computing"; William H. Press,
#  Brian P. Flannery, Saul A. Teukolsky. and William T. Vetterling;
#  Cambridge University Press, 1986.
#
############################################################################

record date1(month, day, year)

procedure calendat(julian)
   local ja, jalpha, jb, jc, jd, je, gregorian
   local month, day, year

   gregorian := 2299161

   if julian >= gregorian then {
      jalpha := integer(((julian - 1867216) - 0.25) / 36524.25)
      ja := julian + 1 + jalpha - integer(0.25 * jalpha)
      }
   else ja := julian

   jb := ja + 1524
   jc := integer(6680.0 + ((jb - 2439870) - 122.1) / 365.25)
   jd := 365 * jc + integer(0.25 * jc)
   je := integer((jb - jd) / 30.6001)
   day := jb - jd - integer(30.6001 * je)
   month := je - 1
   if month > 12 then month -:= 12
   year := jc - 4715
   if month > 2 then year -:= 1
   if year <= 0 then year -:= 1

   return date1(month, day, year)

end