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// CS0452: The type `U' must be a reference type in order to use it as type parameter `UU' in the generic type or method `B.Test<UU>(UU)'
// Line: 13
abstract class A<T>
{
public abstract void Foo<U> (U arg) where U : T;
}
class B : A<int>
{
public override void Foo<U> (U arg)
{
Test (arg);
}
void Test<UU> (UU a) where UU : class
{
}
}
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